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u^2-51u+98=0
a = 1; b = -51; c = +98;
Δ = b2-4ac
Δ = -512-4·1·98
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-47}{2*1}=\frac{4}{2} =2 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+47}{2*1}=\frac{98}{2} =49 $
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